p^2+4p+106=10

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Solution for p^2+4p+106=10 equation: 



p^2+4p+106=10

We move all terms to the left:

p^2+4p+106-(10)=0

We add all the numbers together, and all the variables

p^2+4p+96=0

a = 1; b = 4; c = +96;
Δ = b2-4ac
Δ = 42-4·1·96
Δ = -368
Delta is less than zero, so there is no solution for the equation

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